An average human weighs about 650 n. if each of two average humans could carry 1.0 c of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 650-n weight?

r = 3721.04 m          

Explanation:

Given that,

Weight of human, F = 650 N

Charge on two humans,

We need to find the distance between charges if the electric attraction between them to equal their 650 N weight. It is given by :

r = 3721.04 m

So, the distance between charges is 3721.04 m if the electric attraction between them to equal their 650 N weight. Hence, this is the required solution.

i need to show me the graph so i can give u an answer

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.