An electron is projected with an initial speed v0 = 1.10106m/s into the uniform field between the parallel plates in the figure . assume that the field between the plates is uniform and directed vertically downward, and that the field outside the plates is zero. the electron enters the field at a point midway between the plates.

(a)if the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field.

(b) suppose that in the figure, the electron is replaced by a proton with the same initial speed. would the proton hit one of the plates?

(c) what would be the direction of proton's displacement? upward or downward?

(d) compare the paths traveled by the electron and the proton and explain the differences.

answer: option c.

explanation:

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.