Find the voltage change when: a. an electric field does 12 j of work on a 0.0001-c charge. b. the same electric field does 24 j of work on a 0.0002-c charge.

Explanation:

Given that,

(a) Work done by the electric field is 12 J on a 0.0001 C of charge. The electric potential is defined as the work done per unit charged particles. It is given by :

(b) Similarly, same electric field does 24 J of work on a 0.0002-C charge. The electric potential difference is given by :

Therefore, this is the required solution.

the gas collects in coils that then becomes a liquid that then flows through the coils inside the refrigerator

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