The electrostatic force of attraction between two charged objects separated by a distance of 1.0 cm is given by f. if the distance between the objects were increased to 5.0 cm, what would be the electrostatic force of attraction between them?

New force between them will become times

Explanation:

Let the charge on both the object are and distance between them is is given 1 cm

So r = 1 cm = 0.01 m

Electric force between them is given F

According to Coulomb's between two charges is given by

According to question -----------eqn 1

Now distance is increased by 5 cm so new distance = 5+1 = 6 cm = 0.06 m

So new force ------------------eqn 2

Comparing eqn 1 and eqn 2

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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