The top of a swimming pool is at ground level. if the pool is 2.40 m deep, how far below ground level does the bottom of the pool appear to be located for the following conditions? (the index of refraction of water is 1.333.)

1.80 Meter

Explanation:

The bottom of a water (liquid) container appears to be raised up in comparison to its actual depth because of the refraction. How shallow will the bottom appear depends on the refractive index of the liquid.

The refractive index(n) and apparent and real depth are related as given below:

Given,

n = 1.333

Real depth = 2.40 m

Thus, Apparent depth = 1.80 Meter

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form