Two stars m1 and m2 of equal mass make up a binary star system. they move in a circular orbit that has its center at the midpoint of the line that separates them. if m1-m2-6.95 sm (solar mass), and the orbital period of each star is 2.20 days, find their orbital speed. (the mass of the sun is 1.99x 1030 kg.) km/s m2

V = 365643.04 m/s

Explanation:

mass of the sun = 1.99 x 10^{30} kg

mass of M1 = mass of M2 = 6.95 solar mass = 6.95 x 1.99 x 10^{30} = 13.8305x 10^{30} kg  

orbital period of each star (T) = 2.20 days = 2.20 x 24 x 60 x 60 =190,080 s

gravitational constant (G) = 6.67 x 10^{-11} N m2/kg2

orbital speed (V) =

we need to find the orbital radius (r) before we can apply the formula above and we can get it from Kepler's third law, x k

where

making r the subject of the formula we now have

   (take note that π is shown as )

r = 1.38 x 10^{10} m

Now that we have the orbital radius (r) we can substitute all required values into the formula for orbital speed

orbital speed (V) =

V = 365643.04 m/s

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50

the higher the current the higher the mag field around it the higher the influence on the compass