Apositively charged particle initially at rest on the ground accelerates upward to 160 m/s in 2.10 s. the particle has a charge-to-mass ratio of 0.100 c/kg and the electric field in this region is constant and uniform. what are the magnitude and direction of the electric field? express your answer to two significant digits and include the appropriate units.

The magnitude of the electric field is

Explanation:

Given that,

Time t = 2.10 s

Speed = 160 m/s

Specific charge =Ratio of charge to mass = 0.100 C/kg

We need to calculate the acceleration

Using equation of motion

Put the value into the formula

We need to calculate the magnitude of the electric field

Using formula of electric field

Put the value into the formula

The direction is upward.

Hence, The magnitude of the electric field is

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