A15 g marble moves to the right at 3.5 m/s and makes an elastic head-on collision with a 22 g marble. the final velocity of the 15 g marble is 5.4 m/s to the left, and the final velocity of the 22 g marble is 2.0 m/s to the right.
what is the initial velocity of the 22 g marble?

a) 5.3 m/s to the left
b) 5.3 m/s to the right
c) 4.1 m/s to the right
d) 4.1 m/s to the left

≅-4.1 m/s (-ve for left)

≅4.1 m/s (To the left)

Explanation:

According to the conservation of momentum:

Momentum before collision=Momentum After Collision

Where:

is the 15g marble

is the 22 g marble

is the velocity of 15g marble before collision

is the velocity of 22g marble before collision

is the velocity of 15g marble after collision

is the velocity of 22g marble after collision

Note: -ve sign for left, +ve sign for right

We have to calculate v_2:

Above equation on rearranging will become:

≅-4.1 m/s (-ve for left)

≅4.1 m/s (To the left)

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)