Astudent creates a circuit that consists of a single battery and four resistors that are arranged as shown. how much energy is dissipated by the 2 ω resistor after 120 s if the total current drawn from the battery is 5 a?

6000JOules

Explanation:

My friend this is quite easy.

There is an equation.

The energy is also presumed as heat.

To calculate the heat in a circuit or the energy the equation is H=I(square) RT

Heat= square of current x resistance x time

Here I=5a.

R=2 ohm

T=120s

H= 5x5x2x120=6000J

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the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.  

neglecting air resistance etc etc.,  

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.  

vh = 8 ms-1  

the vertical velocity component has an accelerating force: 'g'.  

using v = u +at where a = g = 9.81 ms-2.  

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2  

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.  

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.  

adding vectorally gives: -  

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

the answer is false

explanation: