Aball is dropped off the side of a bridge. after falling 1.55 s, what is its velocity?

-15.19 m/s

Explanation:

The 1D kinematic equation for velocity is the v = v0 * at.

In this case, v is the final velocity (what we're after), v0 is the initial velocity, a is the acceleration, and t is the time elapsed.

v0 is 0 because at 0 seconds we are just releasing the ball.

a is the acceleration due to gravity as no other factors are specified.

t is the change in time.

v = 0 * -9.8 m/s^2 * 1.55 = -15.19 m/s.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle