Acharge q is located inside a rectangular box. theelectric flux through each of the six surfaces of the box is: electric flux 1 = +1500 n*m^2/c, electric flux 2 = +2200n*m^2/c, electric flux 3 = +4600 n*m^2/c, electric flux 4 = -1800n*m^2/c, electric flux 5 = -3500 n*m^2/c, and electric flux 6 =-5400 n*m^2/c. what is q?

To solve this problem we will apply the laws of gaus that relate the Electric Flow as the charge of the object on the permittivity constant of free space. Mathematically this is

Rearranging to find the charge,

Here

Q = Charge

Electric Flux

Permittivity of free space

The total flux would be

Replacing we have that,

Therefore the charge Q inside a rectangular box is -21.24nC

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .