Atruck is hoisted a certain distance in a garage and therefore has potential energy with respect to the floor. if it were lifted twice as high, it would have as much potential energy.

If the truck were lifted twice as high, it would have twice as much potential energy

Explanation:

Potential energy = mgh

where;

m is mass of the truck (kg)

g is acceleration due to gravity (m/s²)

h is the height above the floor.

Initial Potential Energy, E₁ = mgh₁

When the truck was lifted twice as high, New height (h₂) = 2h₁

New potential Energy, E₂ =mgh₂ = mg(2h₁)

E₂ = 2mgh₁

Recall, E₁ = mgh₁, then substitute in E₁  into E₂

E₂ = 2(mgh₁)

E₂ = 2E₁

Therefore, If the truck were lifted twice as high, it would have twice as much potential energy

unbalanced force

explanation:

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27