Aproton moving to the right at 3.8 enters a region where 56 electic field points ot the left, how far will the proton get and describe its motion

0.07meter

Pointing to the left.

Explanation:

The Electric potential V of the proton is 3.8v. while the Electric Field strength is 56V/m. We first calculate the distance r the proton would travel

E= V/r

r = V/E

r = 3.8V/(56V/m)

r =0.07m.

The proton which is positively charged will move in the direction of the Electric Field that is to the left.

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be subject to a force andchange its motion