If a proton and an electron are released when they are 5.50×10−10 mm apart (typical atomic distances), find the initial acceleration of each of them. express your answer in meters per second squared.

Explanation:

Distance between proton and electron = r = 5.5 x 10⁻¹³ m

Magnitude of charge on electron and proton = 1.67 x 10⁻¹⁹ C

To find their initial acceleration first force between them is:

Initial acceleration of electron and proton are found using

F=ma

a=F/m

a high pressure system is a dense air mass that is usually cooler and drier than the surrounding air. a low pressure system is a less dense air mass that is usually wetter and warmer than the surrounding air.

in general, areas that experience high atmospheric pressure also experience fair weather. low pressure systems can cause the formation of clouds and storms. air usually flows from areas of high pressure to areas of low pressure..