A3-kg object is moving at 5.0 m/s. an 12-n force is applied in the direction of motion and then removed after the object has traveled an additional 6.0 m. what is the work done by this force?

The work done by the force is 109.5 Joules.

Explanation:

It is given that,

Mass of the object, m = 3 kg                                

Speed of the object, v = 5 m/s

Force applied on the object, F = 12 N

Distance covered by the object, d = 6 m

The work done by this force is given by the sum of kinetic energy and potential energy as per work energy theorem as :

W = 109.5 Joules

So, the work done by the force is 109.5 Joules. Hence, this is the required solution.