Aparticle of charge 3.53×10 −8 c experiences a force of magnitude 6.03×10 −6 n when it is placed in a particular point in an electric field. what is the magnitude of the electric field at that point?

Explanation:

Electric field is the ratio of force and charge.

Force, F = 6 x 10⁻⁶ N

Charge, q = 3.53 x 10⁻⁸ C

We have           

Electric field at the location of the charge is 169.97 N/C

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explanation: