Acharge of -3.50 nc is placed at the origin of an xy-coordinate system, and a charge of 1.95 nc is placed on the y axis at y = 3.75 cm .find the distances to the center.

3.72 cm

Explanation:

the coordiante of the negative charge =( 0,0)

the  coordinate of the positive charge = (0,3.75)

the distance simply is  3.72-0 = 3.72 cm

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explanation:

i think if it were me i whould divide 300 dide 15

step-by-step explanation: