Satellite 1 revolves around a planet at the altitude equal to one-half the radius of the planet. the period of revolution of satellite 1 is . what is the period of revolution of an identical satellite 2 that revolves around the same planet at the altitude equal to the radius of the planet?

To calculate the period of satellite orbiting around a planet, we use Kepler's third law;

Square of T = [(4π)/(G*m)] * R^3.

Therefore,

T = sqrt{[(4π)/(G*m)]*R^3}.

T is the period, m is mass orbiting satellite, G is gravitational constant, R is the radius of of the planet, r is the radius of the orbiting satellite.

For Satellite 1, r is one-half of the planet, that is r = (3/2) * R

For satellite 2, r = R

Explanation:

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what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s