A1425 kg car located at < 266, 0, 0 > m has a momentum of < 46000, 0, 0 > kg·m/s. what is its location 11 s later? (express your answer in vector form.)

<621, 0 , 0>

Explanation:

given,

mass of the car ,m = 1425 Kg

location of car = < 266, 0, 0 > m

momentum of the car = < 46000, 0, 0 > kg.m/s

M v_x = 46000

1425 x v_x = 46000

  v_x = 32.28 m/s

  v_y = 0 m/s

  v_z = 0 m/s

Location of the car after 11 s

x = v_x t + 266

x = 32.28 x 11 + 266

x = 621 m

hence, the location of car after 11 s is equal to  <621, 0 , 0>

you would expect a sound wave to speed up. - b)

come closer and become far apart and become steam/gas