Asmall 12.00g plastic ball is suspended by a string in a uniform, horizontal electric field with a magnitude of 10^3 n/c. if the ball is in equilibrium when the string makes a 30 o angle with the vertical, what is the net charge on the ball? q =

The net charge is

Solution:

As per the question:

Mass of the plastic bag, m = 12.0 g =

Magnitude of electric field, E =

Angle made by the string,

Now,

To calculate the net charge, Q on the ball:

Vertical component of the tension in the string,

Horizontal component of the tension in the string,

Now,

Balancing the forces in the x-direction:

                            (1)

Balancing the forces in the y-direction:

where

g = acceleration due to gravity =

Thus

Use T = 0.1357 N in eqn (1):

ingenuity says that the answer is 2.7 m.