Carlota does 2000 j of work on a machine. the machine does 500 j of work. what is the efficiency of the machine?

25%

Explanation:

Efficiency of a machine: This can be defined as the ratio of work output to work input of a machine, expressed in percentage. mathematically, it can be represented as

E(%) = (work output/work input)×100/1 Equation 1

Given: Work output = 500 J, Work input = 2000 J

Substituting into equation 1

E(%) = (500/2000)×100

E(%) = 25%

Hence the efficiency of the machine is 25%

the gas collects in coils that then becomes a liquid that then flows through the coils inside the refrigerator

need to see circuit to get time constant