A 2.5-kg object is dropped from a height of 1000 m. what is the force of air resistance on the object when it reaches terminal velocity

24.5 N

Explanation:

The falling object experiences its weight acting downwards and the air resistance in the opposite direction.

The air resistance increases with velocity so there may come a point, depending on the shape of the object and if there is sufficient height, where these 2 forces are equal.

Since the object has no net forces acting on it it will, according to Newton, no longer accelerate but continue with a constant velocity.

This is called Terminal Velocity.

So:

Air resistance = weight

R = m g

R = 2.5 × 9.8  = 24.5N

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