-In the Bohr model, as it is known today, the electron is imagined to move in a circular orbit about a stationary proton. The force responsible for the electron's circular motion is the electric force of attraction between the electron and the proton. If the speed of the electron were 2.4×105 m/s , what would be the corresponding orbital radius?

-The answer I got was 4x10^-9 , but it is wrong.

(9.0x109) (1.6x10-19 C)2 == 2.304x10-28 Then I divided that by (9.11x10-31 kg)( 2.4 x 105)2 =5.24736 x 10-20

=== 2.304x10-28 / 5.24736 x 10-20 = .000000004

I do not know what I am doing wrong. Please help