A fox is 3.2 m from a 0.5 m tall wall. If it leaps from the ground towards the wall with an initial velocity of 12.0 m/s at an angle of 18.9° above the horizontal, how high off the ground will the fox be when it reaches the wall?

0.7 m.

Explanation:

We are given that

Initial velocity of fox,v=12 m/s

Distance of fox from the ball=3.2 m

Horizontal component of velocity=

Vertical component of velocity=

Time taken by fox to travel in horizontal direction=

Time taken by box to the wall=0.28 s

Formula:

Where

Using the formula

Takine g negative because fox going against to gravity.

Hence, the fox will reach upto height 0.7 m when it reaches the wall

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