Two water manometers are connected to a tank of air. One leg of the manometer is open to 100kPa pressure (absolute) while the other leg is subjected to 90kPa. Find the difference in deflection between both manometers, Delta h_a - Delta h_b.

Deflection between the two nanometers is1.020m

Explanation:

Let ha be for the first manometer=90kpa

Let hb be for the second manometer=100kpa

1000×9.8=9800

Delta(ha)-delta(hb)=(1-0.9)×patm/9800patm

100kpa=100000pa

Therefore

(1 -0.9)×100,000/9800 =0.1×10.204=1.020m

amplitude

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