A 19.2g quantity of dry ice (solid carbon dioxide) is allowed to sublime (evaporate) in an apparatus. Calculate the expansion work done against a constant external pressure of 0.995 atm and at a constant temperature of 22 degrees C. Assume that the initial volume of dry ice is negligible and that CO2 behaves like an ideal gas.

Answer : The expansion work done against a constant external pressure is, -1063.65 J

Explanation :

First we have to calculate the moles of dry ice .

Given:

Molar mass of = 44 g/mole

Mass of = 19.2 g

Now put all the given values in the above expression, we get:

Now we have to calculate the volume of dry ice.

Using ideal gas equation:

where,

P = Pressure of gas = 0.995 atm

V = Volume of gas = ?

n = number of moles  = 0.436 mole

R = Gas constant =

T = Temperature of gas =

Putting values in above equation, we get:

As initially, volume of dry ice is negligible. So,

Volume expanded = Volume of dry ice

Thus,

Expansion work = -(Pressure × Volume)

Expansion work = -0.995 atm × 10.6 L

Expansion work = -10.5 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = -10.5 × 101.3 = -1063.65 J

Therefore, the expansion work done against a constant external pressure is, -1063.65 J

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this