1.3 kg of water, at an initial temperature of 25oC, is heated at a rate of 100 W in a well-insulated container. How much time (in minutes) will it take for the water to reach the boiling point (100oC)

68.25 minutes.

Explanation:

Power = Energy/time or

Power = Heat/time

P = Q/t Equation 1

Q = Pt Equation 2

Where Q = quantity of heat, P = power, t = time.

Also,

Q = cm(t₂-t₁) Equation 3

Where c = specific heat capacity of water, m = mass of water, t₁ = initial temperature of water, t₂ = final temperature of water.

substitute equation 2 into equation 3

Pt = cm(t₂-t₁) Equation 4

make t the subject of the equation

t = cm(t₂-t₁)/P Equation 5

Given: P = 100 W, m = 1.3 kg, t₁ = 25 °C, t₂ = 100 °C.

Constant: 4200 J/kg.K

Substitute into equation 5

t = 1.3(4200)(100-25)/100

t = 409500/100

t = 4095 seconds

t = (4095/60) minutes = 68.25 minutes.

Hence the time it will take the water to reach boiling point = 68.25 minutes

what was the answer?

in this image, you can see solar radiation going through ocean water.

no image, but probably absorption