A uniform electric field is oriented in the −z direction. The magnitude of the electric field is 6500 N/C.
(a) How will the equipotential surfaces associated with this electric field be oriented? parallel to the xy plane parallel to the xz plane parallel to the yz plane
(b) Consider two of the equipotential surfaces; one with a potential of

In a plane parallel to the xy plane.

Explanation:

Direction of uniform electric field is oriented in the −z direction.

a) We know that the direction of equipotential surfaces are always normal to electric field direction. So, equipotential surface will be in a plane perpendicular to electric field that in a plane perpendicular to z-axis that is parallel to the xy plane.

answerscientific theory;