A particle of mass 5 kg is undergoing one-dimensional motion. It is subject to a constant force of 25 N, and has an initial speed of 3 m/s. The force is parallel to the initial velocity, both of which are directed in the positive direction along the axis of motion
(a) what is the change in velocity △v, in meters per second, of the particle between t = 0 and t = 2 s?
(b) What is the displacement △r, in meters, o ,i m, of the particle betwemt-0 and-2 t = 2 s?

(a)10m/s

(b)16 m

Explanation:

We are given that

Mass of particle=m=5 kg

Force=F=25 N

Initial speed=u=3m m/s

a.t=0 and t=2 s

We know that

Force=

Using the formula

Final velocity when t=2 s

Change in velocity=Final velocity-initial velocity

Using the formula

Hence, the change in velocity=10 m/s

(b) t=0 s and t=2 s

We have to find the  displacement (

Using the formula and substitute t=2

Hence,the displacement of the particle between t=0 s and t=2 s=16 m

d.7.5cm is your answer

mass and volume are the answers you are looking for