If a force of 10 N stretches a certain spring 4cm, How much stretch will occur for an applied force of 15 N?

Explanation:

For spring system

Force applied

F = - kx

Where k is the spring constant and x is stretching length of spring. The negative sign indicates that force applied to strech a spring produces a negative acceleration in spring which give rise to restoring force.

Now

In first step

F= 10N

x= 4 cm= 0.04 m

Since k is a constant thus

k= F/x = 10/0.04= 250 N/m

Which will be the spring constant of the spring.

In second step 15 N force is applied to the same string.

Thus, the streching length can be calculated as

x= F / k = 15 N / 250 N/m= 0.06 m = 6 cm

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