Air becomes a conductor when the electric field strength exceeds 3.01 × 106 N/C. Determine the maximum amount of charge that can be carried by a metal sphere 5.0 m in radius. The value of the Coulomb constant is 8.99 × 109 N · m2 /C 2 . Answer in units of C.

8.37×10⁻³ C.

Explanation:

The formula of electric field is given as

E = kq/r² Equation 1

Where E = electric field, q = amount of charge, k = coulomb constant, r = radius of the sphere

make q the subject of the equation

q = Er²/k Equation 2

Given: E = 3.01×10⁶ N/C, r = 5.0 m, k = 8.99×10⁹ Nm²/C².

Substitute into equation 2

q = (3.01×10⁶)(5²)/(8.99×10⁹)

q = (75.25/8.99)×10⁻³

q = 8.37×10⁻³ C.

Hence the maximum amount of charge = 8.37×10⁻³ C.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

the inner core.

good luck: )

klicker