An electric dipole consisting of charges of magnitude 1.50 nC separated by 6.20 mm is in an electric field of strength 1100 N/C. What are (a) the magnitude of the electric dipole moment and (b) the difference between the potential energies for dipole orientations parallel and antiparallel to E

Explanation:

(a) It is known that formula for electric dipole moment is as follows.

          p = qd

             =

             =

Hence, magnitude of the electric dipole moment is .

(b) Now, formula to calculate the difference in potential energy is as follows.

                         = -pE Cos 180 + pE Cos 0

                         = 2pE

                         =

                         =

Thus, we can conclude that difference between the potential energies for dipole orientations parallel and antiparallel to E is .

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft