The planet Krypton has a mass of 8.4 x 1023 kg andradius of 3.4 x 106 m.
What is the acceleration of an object in free fall near thesurface of Krypton? the gravitational constant is 6.6726 x10-11 N x m2 /kg2 . Ans. in unitsof m/s2 .

The acceleration of the object is 4.847m/s^2

Explanation:

Acceleration due to gravity g is given by:

g =(G×M)/R^2

Where G is gravitational constant

M is mass of object

R is radius

g =(6.6726×10^-11)×(8.4×10^23) /(3.4×10^6)^2

g=5.605×10^13/1.156×10^13

g= 4.847m/s^2

found in the nucleus

has mass of one amu

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