A
14.7

g
ice cube is placed into
324

g
of water. Calculate the temperature change in the water upon complete melting of the ice. Hint: Determine how much heat is absorbed by the melting ice and then use
q
=
m
C
Δ
T
to calculate the temperature change. Use the heat of fusion for water to calculate "q"

is the drop in the water temperature.

Explanation:

Given:

Assuming the initial temperature of the ice to be 0° C.

Apply the conservation of energy:

Now from the heat equation:

......................(1)

where:

latent heat of fusion of ice

specific heat of water

change in temperature

Putting values in eq. (1):

is the drop in the water temperature.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2