24-gauge copper wire has a diameter of 0.51 mm. The speaker is located exactly 4.27 m away from the amplifier. What is the minimum resistance of the connecting speaker wire at 20°C? Hint: How many wires are required to connect a speaker!Compare the resistance of the wire to the resistance of the speaker (Rsp = 8 capital omega)

 R = 8.94 10⁻² Ω/m ,    R_sp / R_total = 44.8

Explanation:

The resistance of a metal cable is

         R = ρ L / A

The area of a circle is

          A = π R²

The resistivity of copper is

        ρ = 1.71 10⁻⁸ ohm / m

Let's calculate

       R = 1.71 10⁻⁸  4.27 / (π (0.51 10⁻³)²)

       R = 8.94 10⁻² Ω/m

Each bugle needs two wire, phase and ground

The total wire resistance is

        R_total = 2 R

        R_total = 17.87 10⁻² Ω

Let's look for the relationship between the resistance of the bugle and the wire

      R_sp / R_total = 8 / 17.87 10⁻²

      R_sp / R_total = 44.8

the answer for apex is the lowest

this is poiselle's equation from fluid mechanic in physics. mech eng