What voltage, in kilovolts, is applied to the 9.5 μF capacitor of a heart defibrillator that stores 38.5 J of energy?

The relation of energy in a circuit with a capacitance and determined potential is given under the relation,

Here,

C = Capacitance

V = Voltage,

Rearranging to find the voltage,

Replacing with our values,

Therefore the voltage is 2.84kV

e/c, where e is its total energy

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation