One mole of an ideal gas does 3000 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 atm and volume of 25.0 L. Determine:

a) the initial volume ?
b) the temperature of the gas?
(Note: 1 atm = 1.01 x 105Pa, universal gas constant R = 8.31 J/mol K, 1 L = 10-3m3)

(a) Initial volume will be 7.62 L

(b) Final temperature will be 303.85 K

Explanation:

We have given one mole of ideal gas done 3000 J

So work done W = 3000 J

Let initial volume is and initial pressure ( As pressure is constant )

Final volume = 0.025

Number of moles n = 1

(B) From ideal gas of equation we know that

So

T = 303.85 Kelvin

(B) For isothermal process work done is equal to

So initial volume will be 7.62 L

at right angles to each other