An airplane is flying with a velocity of v0 at an angle of α above the horizontal. When the plane is a distance h directly above a dog that is standing on level ground, a suitcase drops out of the luggage compartment.

Part A
How far from the dog will the suitcase land? You can ignore air resistance.
Take the free fall acceleration to be g.

Explanation:

When the suitcase is being released, it has a horizontal velocity of v0, a vertical velocity of 0 and vertical acceleration of g

The time it takes for it to drop by the vertical distance of α under acceleration g can be solved using the following equation of motion

This is also the time it takes for the suitcase to travel horizontally at the rate of v0. So the horizontal distance it travels is

50 inches should be the resultant vector