A system does 203 J of work on its environment and gains 96.8 J of heat in the process. Find the change in the internal energy of (a) the system and (b) the environment.

a)The change in the internal energy of the system = - 106.2 J

b)The change in the internal energy of the environment =  106.2 J

Explanation:

Given that

The work done by system ,W= 203 J

Heat gain ,Q = 96.8 J

We know that

Q= W + ΔU

ΔU =Change in the internal energy

W=Work done

Q=Heat

Now by putting the values in the above equation we get

96.8 = 203 + ΔU

ΔU = 96.8 - 203 J

ΔU  = - 106.2 J

The change in the internal energy of the system = - 106.2 J

The change in the internal energy of the environment =  106.2 J

do you have a formula possibly