Which of the following liquids will have the lowest freezing point/ A) pure h20 B)aqueous KF(0.50 m) C)aqueous sucrose (0.60 m) D)aqueous glucose (0.60 m) E) aqueous Fel3 (0.24 m)

The liquid having lowest freezing point is

Explanation:

The expression for the depression in freezing point is given as:

Or,

where,

= depression in freezing point

i =  van't Hoff factor

= Cryoscopic constant

m = molality of the solution

For the given options:

Option A:  pure water

Pure water has a freezing point of 0°C

Option B:  aqueous KF (0.50 m)

Value of i = 2

So, molal concentration will be =

Option C:  aqueous sucrose (0.60 m)

Value of i = 1 (for non-electrolytes)

So, molal concentration will be =

Option D:  aqueous glucose (0.60 m)

Value of i = 1  (for non-electrolytes)

So, molal concentration will be =

Option E:  aqueous (0.24 m)

Value of i = 4

So, molal concentration will be =

As, the molal concentration of is the highest, so its freezing point will be the lowest.

Hence, the liquid having lowest freezing point is

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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