A simple circuit consists of a light bulb connected to the terminals of a battery. A voltmeter shows a potential difference of 18.5 V across the light bulb, whereas an ammeter registers a current of 0.485 A in the circuit. Determine the resistance of the bulb.

38.14Ω

Let's solve this question using Ohm's law which states that the current (I) flowing through a conductor is directly proportional to the potential difference or voltage (V) across it. Mathematically;

V =  I R       (i)

Where;

R is the constant of proportionality called resistance of the conductor and is measured in Ohms (Ω)

From the question;

V = 18.5V

I = 0.485A

Substitute these  values into equation (i) as follows;

18.5 = 0.485 x R

Solve for R;

R = 18.5 / 0.485

R = 38.14Ω

Therefore the resistance of the bulb is 38.14Ω

the components of a vector are the parts of the vectors that are to each other.

b perpendicular