The potential difference between the plates of a parallel plate capacitor is 4.00 V. If the plate separation for this capacitor is 6.00 cm, what is the intensity of the electric field between the plates of this capacitor?

66.67 V / m

The electric field intensity (E) between the plates of a capacitor is the ratio of the potential difference (V) between the plates to the distance (d) of separation between the plates. Electric field intensity can be measured in V/m.  It can be written as follows;

E = V / d             (i)

From the question;

V = 4.00V

d = 6.00cm = 0.06m

Substitute these values into the equation above. i.e equation (i) as follows;

E = 4.00 / 0.06

E = 66.67 V / m

Therefore, the electric field intensity between the plates of the capacitor is 66.67 V / m

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray