In the 1st quadrant, an electric field points only in the +x-direction but is non-uniform according to the expression: E⃗ =(2000x+6000x2)x^E→=(2000x+6000x2)x ^ where x is measured in meters. If a positive charge Q = +0.57 C is moved horizontally from x = 26 cm to x = 46 cm, what is the magnitude of the change in electrical potential energy of the charge?

resonant frequency

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s