A body in simple harmonic motion has a displacement x that varies in time t according to the equation x = 5cos(π t + π/3) , where x is in cm and t is in seconds. What is the frequency of the oscillation?

1/2 Hz

Explanation:

A simple harmonic motion has an equation in the form of

where A is the amplitude, is the angular frequency and is the initial phase.

Since our body has an equation of  x = 5cos(π t + π/3) we can equate and solve for frequency f

f = 1/2 Hz

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

true tan speed = ang vel x radius