A crate with a mass of m = 130 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate and the deck is As-0.86. The coefficient of kinetic friction is μk-0.41. Randomized Variables m 130 kg μ,-0.86 Pk=0.41 25% Part (a) Write an expression for the minimum force, F, n, that must be applied to get the block moving from rest. Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining:5 (5% per attempt) detailed view 0 Submit Part (b) What is the magnitude of the force F, n in newtons? Part (c) Write an expression for the force F, that must be applied to keep the block moving at a constant velocity Part (d) what is the magnitude of the force F., in newtons?

In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the system if the initial energy was 2000 j ?

Avalue that describes how heavy an object is and is related to the force of gravity is

Part f - example: finding two forces (part i) two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. the block in (figure 1) has a mass m=10kg and is being pulled by a force f on a table with coefficient of static friction îľs=0.3. four forces act on it: the applied force f (directed î¸=30â above the horizontal). the force of gravity fg=mg (directly down, where g=9.8m/s2). the normal force n (directly up). the force of static friction fs (directly left, opposing any potential motion). if we want to find the size of the force necessary to just barely overcome static friction (in which case fs=îľsn), we use the condition that the sum of the forces in both directions must be 0. using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: fcosî¸â’îľsn=0 fsinî¸+nâ’mg=0 in order to find the magnitude of force f, we have to solve a system of two equations with both f and the normal force n unknown. use the methods we have learned to find an expression for f in terms of m, g, î¸, and îľs (no n).