In a laboratory experiment, a computer determines that the time for a falling steel ball to travel the final 0.80 m before hitting the floor is 0.087 s. With what velocity does the ball hit the floor?

Vf = 9.622 m/s

Explanation:

Distance covered S=0.80m, Time t=0.087s and

g=9.81 m/s²  

Required: Final velocity Vf when it hit the floor

Sol:

We have first find Vi so

Vi=Vit + 0.5 a t2

Vi =8.768m/s

Now Vf= Vi + at

Vf = 9.622 m/s

the answer would be   dignified - apex

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach