A 4 kg ball moves with a velocity of 10m/s wide with a 16kg ball moving with a velocity of 4m/s (a) calculate the velocity of ball in each case they stick together on impact and loss of energy resulting from impact (b) state the principle used to calculate the velocity of the ball.

5.2m/s

Explanation:

Mass, m1 = 4kg

m2= 16kg

Velocity before collision for mass 1, u1 = 10m/s

Velocity before collision for mass 2, u2 = 4m/s.

Velocity after collision, V = ?

From law of conservation of linear momentum

Sum of momentum before collision = sum of momentum after collision.

Remember momentum = mass x velocity

Therefore,

m1u1 +m2u2 = (m1 + m2)V

4x10 + 16x4 = (4+16)V

40+64 = 20V

20V= 104/20

Divide both sides by 20

V = 104/20

V = 5.2m/s

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