If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current for the Pentium Prescott? Note: power is defined as the product of voltage and current. Answer as a percentage of the original voltage between 0 and 100 with up to two decimal places.

Explanation:

power P = v x I

v is voltage and I is current ,

ln P =   ln v  + ln I

differentiating

Δp/p x 100 =  x Δv/v x 100 ( I is constant )

10 =   Δv/v x 100

10 = percentage change in voltage

percentage change in voltage = 10

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge