A 20.00-ohm, 5.00-watt resistor is placed in series with a power supply.(a) What is the maximum voltage that can be applied to the resistor without harmingthe resistor?(b) What would be the current through the resistor?

(a) 10.00V

(b) 0.5V

(a) The power(P) supplied by a resistor of resistance (R) when a voltage(V) is passed across is given by;

P = V² / R       ------------------(i)

From the question;

P = 5.00W

R = 20.00Ω

Substitute these values into equation (i) as follows;

5.00 = V² / 20.00

V² = 5.00 x 20.00

V² = 100.00

V =

Solve for V;

V = 10.00V

Therefore, the maximum voltage that can be applied without harming the resistor is 10.00V

(b) By Ohm's law the current (I) flowing through a resistor of resistance (R) when a voltage (V) is applied is given by;

V = I x R

=> I = V / R             ----------------(ii)

Substitute the values of V and R into equation (ii) as follows;

I = 10.00 / 20.00

I = 0.5A

Therefore, the current through the resistor is 0.5A

need to see circuit to get time constant

probably not if net force is zero