How far (in meters) does a person travel in coming to a complete stop in 40 ms at a constant acceleration of 60g?

d= 0.48 m

Explanation:

Given that

time ,t= 40 m s= 40 x 10⁻³ s

Constant acceleration ,a= - 60 g

We know that g= 10 m/s²

Therefore ,a=- 60 x 10 =- 600 m/s²

We know that

v= u + a t

u=initial speed

v=final sped

t=time

a=acceleration

Now by putting the value

0 = u - 600 x  40 x 10⁻³

u = 24  m/s

The distance cover before coming to stop d is given as

d= 0.48 m

moving ball hits still ball. mover stops, hit ball moves. momentum transfer.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.